To what volume should you dilute 48mL of a 13M stock HNO3
solution to obtain a 0.122 HNO3
solution?
you want to dilute it 13/.122 times, or 106.6times.
That means 1 part acid, 105.5 parts water.
so if one part is 48ml, then you add that much conc acid to 5.07liters of water.
To find out the volume of the stock solution that should be diluted to obtain the desired concentration, we can use the dilution formula:
C1 * V1 = C2 * V2
Where:
C1 = Concentration of the stock solution (13 M)
V1 = Volume of the stock solution to be diluted (unknown)
C2 = Concentration of the desired solution (0.122 M)
V2 = Volume of the desired solution (unknown)
In this case, we know that V1 = 48 mL, C2 = 0.122 M, and we need to find V2.
Rearranging the formula, we have:
V1 = (C2 * V2) / C1
Substituting the given values:
48 mL = (0.122 M * V2) / 13 M
Now, to find V2, we can rearrange the formula again:
V2 = (48 mL * C1) / C2
Plugging in the values:
V2 = (48 mL * 13 M) / 0.122 M
V2 ≈ 5136 mL (or 5.136 L)
Therefore, to obtain a 0.122 M HNO3 solution, you should dilute 48 mL of the 13 M stock solution to a final volume of approximately 5.136 liters.