How much energy is released when 44.5 of water freezes?
energy released = mass water x heat fusion water.
To determine the energy released when water freezes, you need to understand the concept of heat of fusion. The heat of fusion is the amount of energy required to change a substance from a liquid to a solid state at constant temperature and pressure.
The heat of fusion for water is approximately 334 joules per gram. To calculate the energy released when a specific mass of water freezes, you can use the formula:
Energy released = mass of water (in grams) × heat of fusion (in joules per gram)
In this case, you have 44.5 grams of water. So, the calculation would be:
Energy released = 44.5 g × 334 J/g
Multiplying these values gives:
Energy released = 14,863 J
Therefore, approximately 14,863 joules of energy would be released when 44.5 grams of water freezes.