I need to see how to arrange 8-1/5y=10x to mx+b form Is it -1/5y=10x-8? I need the slope and y intercept. Thanks much to who ever helps me. Can anyone show me how to work this?
8 -
8 -(1/5)y = 10x
Solve for y:
-y/5 = 10x - 8,
Multiply both sides by -s:
y = -50x + 40
Slope = -50
y-int. = 40
9
To solve the equation 8 - 1/5y = 10x for y in the slope-intercept form (y = mx + b), you need to isolate the term containing y.
Let's start by simplifying the equation:
8 - 1/5y = 10x
First, we'll eliminate the fraction by multiplying through by 5:
5(8 - 1/5y) = 5(10x)
40 - y/5 = 50x
Next, let's isolate the term containing y by subtracting 40 from both sides:
40 - y/5 - 40 = 50x - 40
-y/5 = 50x - 40
Now, let's multiply through by -1/5 to get y by itself:
(-1/5)(-y/5) = (-1/5)(50x - 40)
y/5 = -10x + 8
Finally, multiply through by 5 to get rid of the fraction:
5(y/5) = 5(-10x + 8)
y = -50x + 40
Now the equation is in the slope-intercept form: y = mx + b, where the slope (m) is -50 and the y-intercept (b) is 40.