12-6x=3[2-4(x-6)]
I KNOW THE ANSWER IS 11 BUT EVERYTIME I
DO THE STEPS IT COMES OUT WRONG. COULD YOU SHOW ME DETAILED STEPS?
Thankyou.
12-6x=3[2-4(x-6)]
12-6x = 3[2 - 4x + 24]
12 - 6x = 6 - 12x + 72
6x = 6 - 12 + 72
6x = 66
x = 11
Be sure to do the steps in the brackets first. This site has a detailed explanation of the order of operations.
http://www.purplemath.com/modules/orderops.htm
Correction: Do the calculations in parentheses first.
mean, median, mode, and range
Sure! Let's solve the equation step by step:
1. Start by simplifying both sides of the equation. Distribute the 3 on the right side of the equation:
12 - 6x = 3[2 - 4(x - 6)]
12 - 6x = 3[2 - 4x + 24] (apply the distributive property)
12 - 6x = 3[-4x + 26]
12 - 6x = -12x + 78 (simplify within the brackets)
2. Next, distribute the 3 on the right side one more time:
12 - 6x = -12x + 78
12 - 6x = -12x + 78
12 - 6x = -12x + 78
12 - 6x = -12x + 78 (no additional simplification needed)
3. Now, let's isolate the x terms. Get rid of the -12x term on the right side by adding 12x to both sides of the equation:
12 - 6x + 12x = -12x + 78 + 12x
12 + 6x = 78 (simplify the equation)
4. Next, isolate the x term by subtracting 12 from both sides:
12 + 6x - 12 = 78 - 12
6x = 66 (simplified the equation)
5. Finally, divide both sides of the equation by 6 to solve for x:
(6x) / 6 = 66 / 6
x = 11
So, the solution to the equation 12 - 6x = 3[2 - 4(x - 6)] is x = 11.