i cant figure out how to solve this?
T with two over powe +7T-18+0
so far if figure out T+ but i dunno what
7 x 7 (For T being to the power of 2)
49-18+0 = 31
so t=31
To solve the equation T² + 7T - 18 = 0, you can use the quadratic formula or factorization.
The quadratic formula is x = (-b ± √(b² - 4ac)) / 2a, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.
In this case, the coefficients are:
a = 1 (coefficient of T²)
b = 7 (coefficient of T)
c = -18 (constant)
Using the quadratic formula:
T = (-7 ± √(7² - 4*1*(-18))) / 2*1
T = (-7 ± √(49 + 72)) / 2
T = (-7 ± √121) / 2
T = (-7 ± 11) / 2
This gives us two possible solutions:
1. T = (-7 + 11) / 2 = 4 / 2 = 2
2. T = (-7 - 11) / 2 = -18 / 2 = -9
Therefore, the solutions for the equation T² + 7T - 18 = 0 are T = 2 and T = -9.
If you were referring to "T+" in your question, it is not clear what you are trying to convey. Please provide more information or context so that I can assist you better.