what is the relative humidity of a
kilogram of air at 25 degrees celcious that contains 10grams of water vapor
To calculate the relative humidity, we need to know the maximum amount of water vapor the air can hold at 25 degrees Celsius, also known as the saturation vapor pressure.
One way to find the saturation vapor pressure is by using a formula called the Clausius-Clapeyron equation. However, this equation involves complex calculations and requires knowing various constants.
A simpler approach is to use a chart or online calculator to find the saturation vapor pressure at 25 degrees Celsius. This will give us the maximum amount of water vapor the air can hold under those conditions.
Once we have the saturation vapor pressure, we can compare it to the actual amount of water vapor in the air to determine the relative humidity. The formula for relative humidity is:
Relative Humidity = (Actual Vapor Pressure / Saturation Vapor Pressure) * 100
In this case, we need to convert the given mass of water vapor (10 grams) to the vapor pressure in Pascals (Pa). This can be done using the formula:
Vapor Pressure (Pa) = (Mass of Water Vapor / Molar Mass of Water) * Ideal Gas Constant * Temperature
By substituting the values for mass of water vapor (10 grams), molar mass of water (18 g/mol), the ideal gas constant (8.314 J/(mol·K)), and the temperature (25 degrees Celsius converted to Kelvin: 25 + 273.15 = 298.15 K), we can find the actual vapor pressure.
Then, dividing the actual vapor pressure by the saturation vapor pressure and multiplying by 100 will give us the relative humidity.