7x^2+58x-45?
srry no clue
(7x-5)(x+9)
(I solved the corresponding quadratic equation using the formula and got
x = 7/5 and x = -9
I then formed the factors from that)
To solve the quadratic equation 7x^2 + 58x - 45, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 7, b = 58, and c = -45. Substituting the values into the quadratic formula:
x = (-(58) ± √((58)^2 - 4(7)(-45))) / (2(7))
Now we simplify the equation:
x = (-58 ± √(3364 + 1260)) / 14
x = (-58 ± √(4624)) / 14
x = (-58 ± 68) / 14
So the two solutions for the given quadratic equation are:
x1 = (-58 + 68) / 14 = 10 / 14 = 5 / 7
x2 = (-58 - 68) / 14 = -126 / 14 = -9
Therefore, the solutions to the quadratic equation 7x^2 + 58x - 45 are x = 5/7 and x = -9.