In the same location at the same time of day, two trees casts a shadow. The 60-ft tree casts a 12 ft shadow, and the other trees casts a 4 ft shadow. How tall is the other tree?
A. 20 ft
B. 18 ft
C. 52 ft
D. 76 ft
How do I solve this.. Im confused again...
Set up this proportion and cross multiply. Solve for x.
60/12 = x/4
thank you for trying to help me. but im still confused. Im not very good at math. sorry
What you're saying in this proportion is:
60 is to 12 as an unknown is to 4.
60/12 = x/4
12x = 240
Divide both sides of the equation by 12 to find the value of x.
ooooohhhhhhhh ok... thank you so much!!!!
is there any way u can help me with my other math problem?
You're very welcome.
I'm sorry, but I don't remember how to do your other math problem. I'm basically a social studies and English teacher.
oh ok. thank you any ways! i appreciate it.
To solve this problem, you can use the concept of proportions. The ratio of the height of a tree to the length of its shadow should be the same for both trees since they are in the same location at the same time of day.
Let's call the height of the other tree "x". So we have the following proportion:
60 ft / 12 ft = x / 4 ft
To find the value of "x", we can cross-multiply:
60 ft * 4 ft = 12 ft * x
240 ft = 12 ft * x
Next, divide both sides of the equation by 12 ft to isolate "x":
240 ft / 12 ft = x
20 ft = x
Therefore, the height of the other tree is 20 ft.
So the answer is A. 20 ft.