Can someone help me solve this:
(j^5)^-7
Thanks!
Think of algebra in this way.
When you have (j^x)^y
it will equal J^(x*y)
and example is (j^2)^3=J^(2*3)=J^(6)
or (J^-10)^2=J^-20
Hope this helps
(j^5)^-7
Thanks!
When you have (j^x)^y
it will equal J^(x*y)
and example is (j^2)^3=J^(2*3)=J^(6)
or (J^-10)^2=J^-20
Hope this helps