Find u X v, where Q is the angle between u and v.
magnitude of u =4
magnitude of v=10
Q=2pi/3
The Q is the part that is throwing me off. I do not know where to start.
To find the product u x v, where Q is the angle between u and v, you can use the following formula:
u x v = |u| |v| sin(Q) n
where |u| is the magnitude of vector u, |v| is the magnitude of vector v, Q is the angle between the two vectors, sin(Q) is the sine of the angle, and n is the unit vector perpendicular to the plane containing vectors u and v.
In your case, you are given:
|u| = 4
|v| = 10
Q = 2pi/3
First, you need to calculate the sine of the angle Q. Since sin(Q) is a trigonometric function, you can calculate it directly using the angle Q:
sin(Q) = sin(2pi/3)
To find this value, you can use a scientific calculator or an online trigonometric calculator.
Once you have the value of sin(Q), you can substitute it into the formula:
u x v = |u| |v| sin(Q) n
You already have the magnitudes of u and v, so you can substitute those values too:
u x v = (4) (10) sin(Q) n
Finally, you can simplify the expression by calculating the product of the magnitudes:
u x v = 40 sin(Q) n
So the result is 40 sin(Q) n.