lim sinx
as x approaches pie/r
That would just be the sine of pi/r.
The limit value would depend upon what r is. There are no singularities, such as 0/0. Are you sure you copied the problem correctly?
That's how the question reads. these are the choices for answers
A) -(2^1/2)/2
B) (2^1/2)/2
C) (2^-1/2)/4
D) DOES NOT EXIST
E) -(2^(-1/2))/4
I'm assuming since there is no value for R then the answer does not exist?
The question choices make no sense. I suspect a typo error regarding the "r" term, perhaps a teacher error. A limit does exist, and it is sin pi/r
To evaluate the limit of sin(x) as x approaches π/3, we can directly substitute the value of π/3 into the expression.
lim sin(x) = sin(π/3)
The sine of π/3 can be calculated using the unit circle or a calculator. The value of sin(π/3) is √3/2.
Therefore, the limit of sin(x) as x approaches π/3 is √3/2.