Answer the following for a face centered unit cell. answers should be numerical. r=6.00
edge in terms of r, the lattice pt radius
i know that for a primitive cubic unit cell, you would muliply 2 by 6 = 12. but what formula would u use for a FCC???
Please help. thanks
(12^2) +(12^2) = x
sqrt(x)=ans
^wrong
I don' understand the first two sentences (actually only parts of sentences) but the radius and edge length of the unit cell for the fcc is
4r=a*21/2
There are 4 atoms/unit cell for a fcc.
To find the edge length of a face-centered unit cell (FCC) in terms of the lattice point radius (r), you can use the formula:
Edge length (a) = 4√2 * r
In the case where r = 6.00, you can substitute this value into the formula to calculate the edge length:
Edge length (a) = 4√2 * 6.00
Calculating the numerical answer:
Edge length (a) = 4 * 1.414 * 6.00
Edge length (a) ≈ 33.94
So, the approximate edge length of a face-centered unit cell when the lattice point radius is 6.00 is 33.94 units.