find the v of an object that has fallen 92 ft round to the nearest 100th
To find the final velocity of an object that has fallen 92 ft, we can use the kinematic equation for free fall:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity (assumed to be 0 for an object in free fall)
a = acceleration due to gravity (32 ft/s^2)
s = distance fallen (92 ft)
Plugging in the values, we get:
v^2 = 0 + 2 * 32 * 92
v^2 = 5888
v ≈ √5888
v ≈ 76.72 ft/s
Therefore, the final velocity of the object that has fallen 92 ft is approximately 76.72 ft/s.