Find the range of the given data set.
51, 13, 98, 42, 76, 28
(1 point)
Responses
85
98
23
13
The range is the difference between the largest and smallest numbers in the data set.
The largest number is 98 and the smallest number is 13.
Therefore, the range is 98 - 13 = 85.
So, the correct answer is 85.
Find the interquartile range of the given dataset.
11, 13, 22, 17, 14, 21, 27, 15
(1 point)
Responses
6.5
6.5
21.5
21.5
8
8
13.5
To find the interquartile range, we first need to find the first quartile (Q1) and the third quartile (Q3) of the data set.
First, let's rearrange the data set in ascending order:
11, 13, 14, 15, 17, 21, 22, 27
Q1 is the median of the lower half of the data set. This is the median of the numbers 11, 13, 14, and 15:
Q1 = (13 + 14) / 2 = 13.5
Q3 is the median of the upper half of the data set. This is the median of the numbers 17, 21, 22, and 27:
Q3 = (21 + 22) / 2 = 21.5
Now, we can calculate the interquartile range (IQR):
IQR = Q3 - Q1
IQR = 21.5 - 13.5
IQR = 8
Therefore, the interquartile range is 8.
So, the correct answer is 8.
The heights in inches of six basketball players at a local high school are given as a dataset.
70, 78, 74, 82, 68, 75
Find the range and the interquartile range of the dataset.
(1 point)
Responses
The range is 14, and the interquartile range is 4.5.
The range is 14, and the interquartile range is 4.5.
The range is 5, and the interquartile range is 8.
The range is 5, and the interquartile range is 8.
The range is 14, and the interquartile range is 8.
The range is 14, and the interquartile range is 8.
The range is 14, and the interquartile range is 74.5.
A.B.C.D
To find the range of the dataset, we need to identify the difference between the maximum and minimum values:
Maximum value: 82
Minimum value: 68
Range = Maximum value - Minimum value
Range = 82 - 68
Range = 14
To find the interquartile range (IQR) of the dataset, we need to calculate the difference between the third quartile (Q3) and the first quartile (Q1). First, let's arrange the data in ascending order:
68, 70, 74, 75, 78, 82
Q1 (lower quartile) = Median of the lowest half of the data set = (70 + 74) / 2 = 72
Q3 (upper quartile) = Median of the highest half of the data set = (75 + 78) / 2 = 76.5
IQR = Q3 - Q1
IQR = 76.5 - 72
IQR = 4.5
Therefore, the correct response is:
The range is 14, and the interquartile range is 4.5.
So, option A is the correct response.
wrong
Apologies for the mistake. Let's reevaluate the calculations.
For the given dataset: 70, 78, 74, 82, 68, 75
First, let's find the range:
Maximum value: 82
Minimum value: 68
Range = Maximum value - Minimum value
Range = 82 - 68
Range = 14
Now, let's find the quartiles:
Arranging the data in ascending order: 68, 70, 74, 75, 78, 82
Q1 (lower quartile) = (70 + 74) / 2 = 72
Q3 (upper quartile) = (75 + 78) / 2 = 76.5
Now, calculate the interquartile range (IQR):
IQR = Q3 - Q1
IQR = 76.5 - 72
IQR = 4.5
So, the correct answer should be: The range is 14, and the interquartile range is 4.5.
Therefore, option A is indeed the correct response.
nope
I apologize for the errors in my previous responses. Let's recalculate the range and interquartile range correctly for the dataset: 70, 78, 74, 82, 68, 75.
First, let's calculate the range:
Maximum value: 82
Minimum value: 68
Range = Maximum value - Minimum value
Range = 82 - 68
Range = 14
Now, let's find the quartiles:
Arranging the data in ascending order: 68, 70, 74, 75, 78, 82
Q1 (lower quartile) = 70
Q3 (upper quartile) = 78
Now, calculate the interquartile range (IQR):
IQR = Q3 - Q1
IQR = 78 - 70
IQR = 8
Therefore, the correct answers are:
The range is 14, and the interquartile range is 8.
So, the correct response should be: The range is 14, and the interquartile range is 8.
Thank you for your patience.
Use the table to answer the question.
Color Frequency
green 4
white 1
blue 6
red 3
Use the mode to describe the distribution of the dataset. Anjali makes an art project using the sheets of construction paper shown in the table. What is the mode of the data?
(1 point)
Responses
white
white
blue
blue
green
green
red