Graph a right triangle with the two points forming the hypotenuse. Using the sides, find the distance between the two points, to the nearest tenth (if necessary). (7,-7) and (9,-9)
what is leg 1 and 2
Using the coordinates (7, -7) and (9, -9), we can see that the two points form a right triangle with the hypotenuse being the line connecting the two points.
The two legs of the triangle can be found by taking the differences in the x and y coordinates of the two points.
Leg 1:
x1 = 7
x2 = 9
y1 = -7
y2 = -9
Leg 1 = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Leg 1 = sqrt((9 - 7)^2 + (-9 - (-7))^2)
Leg 1 = sqrt(2^2 + (-2)^2)
Leg 1 = sqrt(4 + 4)
Leg 1 = sqrt(8)
Leg 1 ≈ 2.8
Leg 2:
Leg 2 will be the same as Leg 1, as it is a right triangle the legs will be the same length.
Therefore, the distance between the two points is approximately 2.8 units.