A girl travels 15km due west, then 5km due north. How far is she from the starting point. Show the diagram
To find the distance from the starting point, we can use the Pythagorean theorem because the girl traveled in a straight line.
Let's represent the starting point as point O, the 15km westward distance as line segment AB, and the 5km northward distance as line segment BC. Then, we can draw line segment AC to represent the distance from the starting point.
According to the Pythagorean theorem, the square of the hypotenuse (AC) is equal to the sum of the squares of the other two sides (AB and BC).
Therefore, AC^2 = AB^2 + BC^2 = (15km)^2 + (5km)^2
AC^2 = 225km^2 + 25km^2
AC^2 = 250km^2
AC = √250km
AC ≈ 15.81km
Therefore, the girl is approximately 15.81km away from the starting point.
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B (15km)
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C (5km) --------- A (Starting Point)
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