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A box contains three red marbles and six blue marbles. What is the probability of selecting at random, without replacement, two blue marbles?

Responses

1/9
1/12
5/12
4/9

First, calculate the total number of marbles in the box: 3 red + 6 blue = 9 marbles total

Next, calculate the probability of selecting the first blue marble: 6 blue / 9 total = 2/3

Since we are selecting without replacement, there will now be 8 marbles left in the box, with 5 of them being blue.

Calculate the probability of selecting the second blue marble: 5 blue / 8 total = 5/8

To find the overall probability of selecting two blue marbles, multiply the probabilities together: (2/3) * (5/8) = 10/24 = 5/12

Therefore, the probability of selecting at random, without replacement, two blue marbles is 5/12.