Given : circle with centre O and PQ. OR perpendicular to PQ. QR =6 units and PQ =16 units. calculate the length of OQ.
Since OR is perpendicular to PQ, we can use the Pythagorean theorem to calculate the length of OQ.
PQ^2 = QR^2 + PR^2
16^2 = 6^2 + PR^2
256 = 36 + PR^2
PR^2 = 256 - 36
PR^2 = 220
PR = √220
PR = 2√55
Since OQ is the radius of the circle, OQ = PR/2 = (2√55)/2 = √55
Therefore, the length of OQ is √55 units.