3x+6y=21
-5x+2y=13
Solve this using elimination process
To solve this system of equations using the elimination method, we need to first choose either x or y to eliminate by adding or subtracting the two equations. Let's choose to eliminate y in this case.
First, multiply the second equation by 3 to have the coefficients of y be equal in both equations:
-5x + 2y = 13
Multiply by 3:
-15x + 6y = 39
Now, we have:
3x + 6y = 21
-15x + 6y = 39
Adding these two equations will eliminate y:
(3x + 6y) + (-15x + 6y) = 21 + 39
-12x = 60
Divide by -12 on both sides to solve for x:
x = -5
Now, substitute the value of x back into one of the original equations:
3(-5) + 6y = 21
-15 + 6y = 21
6y = 36
y = 6
Therefore, the solution to the system of equations is x = -5 and y = 6.