Bomai place 7 mol of ammonia in 4L flask.at equilibrium 0.2M ammonium was found in the flask.
1.write the balanced chemical reaction for the above reaction?
2.what is the equilibrium constant kc for this reaction?
3.what are conjugate Acids and base for the reaction in 1?
1. Balanced chemical reaction:
2NH3 (g) ⇌ 2NH4+ (aq) + 2OH- (aq)
2. To find the equilibrium constant Kc, we first need to write the expression for the equilibrium constant using the concentrations of the products and reactants:
Kc = [NH4+]^2/[NH3]
Given that the concentration of NH4+ is 0.2M, and the initial concentration of NH3 is 7 moles in a 4L flask (1.75M), we can calculate Kc as:
Kc = (0.2)^2/(1.75) = 0.0229
Therefore, the equilibrium constant Kc for this reaction is 0.0229.
3. The conjugate acid of NH3 is NH4+ and the conjugate base of NH4+ is NH3. In the balanced chemical reaction, NH3 acts as a base and accepts a proton (H+) to form NH4+, making NH3 the conjugate base. Similarly, NH4+ releases a proton to form NH3, making NH4+ the conjugate acid.