Given f(x)=sin x and g(x)=cos x, show that f(g(pi/2))=0.
To find f(g(pi/2)), we first need to find g(pi/2):
g(pi/2) = cos(pi/2) = 0
Now, we substitute this value into f(x):
f(g(pi/2)) = f(0) = sin(0) = 0
Therefore, f(g(pi/2)) = 0.
g(pi/2) = cos(pi/2) = 0
Now, we substitute this value into f(x):
f(g(pi/2)) = f(0) = sin(0) = 0
Therefore, f(g(pi/2)) = 0.