Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 50 in increments of 10. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 45 right parenthesis, left parenthesis 2 comma 25 right parenthesis, left parenthesis 3 comma 15 right parenthesis, and left parenthesis 4.5 comma 0 right parenthesis. 13 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
y= ____
-10x + 45
Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 30 in increments of 2. Multiple points are plotted around a line that points upward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 12 right parenthesis, left parenthesis 4 comma 16 right parenthesis, and left parenthesis 6 comma 18 right parenthesis. 12 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
y= ____
0.5x + 12
That's wrong.
I apologize for the mistake. Let's find the equation properly:
To start, let's find the slope using two points (0, 12) and (3, 18):
slope (m) = (y2 - y1) / (x2 - x1)
slope = (18 - 12) / (3 - 0)
slope = 6 / 3
slope = 2
Next, let's choose one of the points, (0, 12), and plug it into the slope-intercept formula y = mx + b to find the y-intercept 'b':
12 = 2(0) + b
12 = b
Therefore, the equation in slope-intercept form of the trend line is:
y = 2x + 12
That's wrong again.
I apologize for the mistake. Let's correct it.
To find the equation of the trend line, we need to calculate the slope (m) first using two points that lie on the line. Let's use the points (0, 12) and (6, 18):
m = (y2 - y1) / (x2 - x1)
m = (18 - 12) / (6 - 0)
m = 6 / 6
m = 1
Now that we have the slope, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
Using the point (0, 12):
y - 12 = 1(x - 0)
y - 12 = x
y = x + 12
Therefore, the equation in slope-intercept form of the trend line is:
y = x + 12