A poll is conducted to determine who is most likely to win the election for town mayor. Two random samples of 500 residents each are polled. The data is as follows.
candidate A candidate B total
sample 1 346 154 500
sample 2 248 252 500
What percentage of the total polled residents would vote for candidate A as the town mayor
To calculate the percentage of residents who would vote for candidate A as the town mayor, we need to add up the number of residents from each sample who would vote for candidate A.
From sample 1, 346 residents would vote for candidate A.
From sample 2, 248 residents would vote for candidate A.
So, the total number of residents who would vote for candidate A is 346 + 248 = 594.
Out of a total of 1000 residents (500 from each sample), 594 residents would vote for candidate A.
Therefore, the percentage of residents who would vote for candidate A as the town mayor is (594/1000) * 100% = 59.4%.
Therefore, 59.4% of the total polled residents would vote for candidate A as the town mayor.
To determine the average height of trees in a national forest, 10 trees are randomly selected. Their heights in feet are 85.4, 87.6, 85.6, 85.9, 85.3, 84.9, 84.0, and 85.2. To ensure the accuracy of the data, another set of ten trees is randomly selected. Their heights are 87.1, 88.0, 84.2, 85.3, 86.5, 84.2, 84.1, 85.2, and 87.3. What is the difference between the mean heights of the trees of these two randomly samples?
To find the mean height of trees in each randomly selected sample, we first need to calculate the sum of heights in each sample and then divide by the number of trees in the sample.
For the first sample:
Sum of heights = 85.4 + 87.6 + 85.6 + 85.9 + 85.3 + 84.9 + 84.0 + 85.2 = 694.9
Mean height = 694.9 / 8 = 86.8625 feet
For the second sample:
Sum of heights = 87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 84.1 + 85.2 + 87.3 = 687.9
Mean height = 687.9 / 9 = 76.4333 feet
Therefore, the mean height of the first sample is 86.8625 feet and the mean height of the second sample is 76.4333 feet.
The difference between the mean heights of the two samples is:
86.8625 - 76.4333 = 10.4292 feet
Therefore, the difference between the mean heights of the trees in the two randomly selected samples is 10.4292 feet.
I am afraid that is incorrect
I apologize for the mistake. Let's recalculate the mean heights and the difference between the mean heights of the two samples:
First Sample:
Sum of heights = 85.4 + 87.6 + 85.6 + 85.9 + 85.3 + 84.9 + 84.0 + 85.2 = 694.9
Mean height = 694.9 / 8 = 86.8625 feet
Second Sample:
Sum of heights = 87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 84.1 + 85.2 + 87.3 = 682.9
Mean height = 682.9 / 9 = 75.88 feet
The difference between the mean heights of the two samples is:
86.8625 - 75.88 = 10.9825 feet
Therefore, the corrected difference between the mean heights of the trees in the two randomly selected samples is 10.9825 feet. Thank you for pointing out the error.
still wrong.
I apologize for the errors in my previous responses. Let's recalculate the mean heights and the difference between the mean heights of the two samples:
First Sample:
Sum of heights = 85.4 + 87.6 + 85.6 + 85.9 + 85.3 + 84.9 + 84.0 + 85.2 = 693.9
Mean height = 693.9 / 8 = 86.7375 feet
Second Sample:
Sum of heights = 87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 84.1 + 85.2 + 87.3 = 686.9
Mean height = 686.9 / 9 = 76.32 feet
The difference between the mean heights of the two samples is:
86.7375 - 76.32 = 10.4175 feet
Therefore, the correct difference between the mean heights of the trees in the two randomly selected samples is 10.4175 feet. Thank you for your patience.