use ideal gas law to figure out. how many liters of hydrogen gas can be produced of hydrogen gas can be produced at 300 k and 104 kpa if 20 grams of sodium metal is reaced with water according to the following equation
2 Na + 2 H2O -> 2 NaOH + H2
First, we need to calculate the moles of Na involved in the reaction. The molar mass of Na is 23 g/mol.
Therefore, moles of Na = 20 g / 23 g/mol = 0.87 mol
From the balanced equation, we can see that 2 moles of Na react to produce 1 mole of H2 gas.
Therefore, moles of H2 produced = 0.87 mol / 2 = 0.435 mol
Next, we need to calculate the volume of H2 gas produced using the ideal gas law equation:
PV = nRT
Where:
P = 104 kPa = 104000 Pa
V = volume of gas in liters
n = moles of gas = 0.435 mol
R = ideal gas constant = 8.31 L*kPa/mol*K
T = temperature in Kelvin = 300 K
Rearranging the equation to solve for V:
V = (nRT) / P
V = (0.435 mol * 8.31 L*kPa/mol*K * 300 K) / 104000 Pa
V = 1.025 L
Therefore, 1.025 liters of hydrogen gas can be produced at 300 K and 104 kPa when 20 grams of sodium metal is reacted with water.