A number from the list {2, 4, 5, 7, 9, 10, 12, 15, 18, 20} is to be picked at random. What is the probability of getting an even number? Write your answer in the simplest form of fraction .
There are 10 numbers in the list, out of which 5 are even (2, 4, 10, 12, 18).
Therefore, the probability of getting an even number is 5/10, which simplifies to 1/2.
So, the probability of getting an even number is 1/2.
nope
I apologize for the mistake.
There are 10 numbers in the list, out of which 5 are even (2, 4, 10, 12, 18).
Therefore, the probability of getting an even number is 5/10, which simplifies to 1/2.
So, the probability of getting an even number is 1/2.
its not 1/2
I apologize for my error in the previous responses.
There are a total of 10 numbers in the list, out of which 5 are even numbers {2, 4, 10, 12, 18}.
The probability of selecting an even number at random is given by:
Number of favorable outcomes (even numbers) = 5
Total number of outcomes = 10
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 5 / 10
Probability = 1 / 2
Therefore, the probability of getting an even number is 1/2.
its 3/5 oml
Apologies for the error in the previous responses. Let's clarify this:
Total number of elements in the list = 10
Number of even numbers in the list = 5 (2, 4, 10, 12, 18)
Probability of selecting an even number at random = Number of even numbers / Total number of elements
= 5 / 10
= 1 / 2
Therefore, the probability of getting an even number is 1/2.