Which set of ordered pairs does not represent a function?
Answer
Multiple Choice Answers
left curly bracket, left bracket, minus, 1, comma, minus, 5, right bracket, comma, left bracket, 5, comma, 7, right bracket, comma, left bracket, minus, 3, comma, 4, right bracket, comma, left bracket, minus, 3, comma, 9, right bracket, right curly bracket{(−1,−5),(5,7),(−3,4),(−3,9)}
left curly bracket, left bracket, minus, 9, comma, minus, 6, right bracket, comma, left bracket, 1, comma, 5, right bracket, comma, left bracket, minus, 1, comma, 3, right bracket, comma, left bracket, 5, comma, 5, right bracket, right curly bracket{(−9,−6),(1,5),(−1,3),(5,5)}
left curly bracket, left bracket, 2, comma, minus, 5, right bracket, comma, left bracket, minus, 9, comma, 9, right bracket, comma, left bracket, 6, comma, 0, right bracket, comma, left bracket, 3, comma, 9, right bracket, right curly bracket{(2,−5),(−9,9),(6,0),(3,9)}
left curly bracket, left bracket, 4, comma, 0, right bracket, comma, left bracket, 2, comma, minus, 6, right bracket, comma, left bracket, 5, comma, 0, right bracket, comma, left bracket, 0, comma, 5, right bracket, right curly bracket{(4,0),(2,−6),(5,0),(0,5)}
The set of ordered pairs that does not represent a function is:
{(4,0),(2,−6),(5,0),(0,5)} because it has two pairs with the x-value of 0, which violates the definition of a function where each input (x-value) can only have one output (y-value).