A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana (1 point) 21/100; 7/80; 3/5; 7/76
To calculate the probability of selecting an apple and a banana, we first need to determine the total possible combinations of picking 2 fruits from the basket.
Total fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Total possible combinations of picking 2 fruits = 20C2 = (20*19) / (2*1) = 190
Now, let's calculate the number of ways to select an apple and a banana.
Number of ways to select an apple = 7C1 = 7
Number of ways to select a banana = 5C1 = 5
Total number of ways to select an apple and a banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = Number of ways to select an apple and a banana / Total possible combinations
= 35 / 190
= 7 / 38
So, the probability of selecting an apple and a banana is 7/38.