Quadrilateral TUVW is a rhombus. What is m∠UVX?
Since TUVW is a rhombus, all four sides are congruent. This means that angle U = angle V = angle W = angle T.
Since the sum of the angles of a quadrilateral is 360 degrees, we can find the measure of each angle by dividing 360 by 4.
360 / 4 = 90 degrees
Therefore, m∠UVX = 90 degrees.
incorrect is was 28.
Apologies for the mistake. Let me correct it:
Since a rhombus has opposite angles that are congruent, we know that angle U is congruent to angle W, and angle V is congruent to angle T. This means that m∠TUV = m∠VW = m∠WXT = m∠TXU = 90 degrees each.
If ∠UVW = 90 degrees, then we know that the sum of the angles within triangle UVX is 180 degrees. Since the triangle is isosceles, we can divide the remaining angles equally to find m∠UVX:
180 - 90 = 90 degrees remaining for angles UVX.
Since UVX is isosceles, m∠U = m∠V, so m∠UVX = 90 / 2 = 45 degrees.
Therefore, m∠UVX = 45 degrees. Thank you for correcting me.
Quadrilateral BCDE is a rhombus. What is BE?
c+37
4c+25
B
C
D
E
In a rhombus, all four sides are congruent, so BC = CD = DE = EB.
Given the options, the answer is: B