Pure water is made up of oxygen and hydrogen. Each gram of water contains 0.111 g of hydrogen. About how much hydrogen is in 79.2 g of pure water?
To find out how much hydrogen is in 79.2 g of pure water, we can first determine the proportion of hydrogen in water.
Since each gram of water contains 0.111 g of hydrogen, we can set up a proportion:
0.111 g of hydrogen is to 1 g of water as x g of hydrogen is to 79.2 g of water
0.111/1 = x/79.2
0.111 = x/79.2
Cross multiply:
0.111 * 79.2 = x
8.7872 = x
Therefore, there are approximately 8.79 grams of hydrogen in 79.2 grams of pure water.
A. 43 g
B. 230 g
C. 8 g
D. 23 g
The correct answer is C. 8 g
There are approximately 8.79 grams of hydrogen in 79.2 grams of pure water. Rounded to the nearest whole number, this would be 8 grams.