A gas sample has a volume of 125 mL at 91.0 kPa. What is the volume at 101 kPa?
O 135 mL
O 73.5 mL
O 139 mL
O 113 mL
Using Boyle's Law (P1V1 = P2V2), we can rearrange the formula to solve for V2:
P1V1 = P2V2
(91.0 kPa)(125 mL) = (101 kPa)(V2)
11375 = 101V2
V2 = 113.1188 mL
Rounding to the appropriate number of significant figures, the volume at 101 kPa is 113 mL.
Therefore, the closest answer choice is 113 mL.