The volumes of two similar figures are given. The surface area of the larger figure is given. Find the surface area of the smaller figure.
Upper Vequals1920 m cubed
Upper Vequals3750 m cubed
S.A.equals1600 m squared
Question content area bottom
Part 1
The surface area of the smaller figure is
enter your response here m squared.
Since the volumes of the two figures are in a ratio of 1920:3750, the surface areas of the figures will be in a ratio of (1920)^(2/3):(3750)^(2/3).
Calculating the ratio:
(1920)^(2/3) = 40(3)^2 = 360
(3750)^(2/3) = 75(5)^2 = 375
The surface area of the smaller figure is 360 m squared.
the smaller volume is 1920m^3
I apologize for the confusion. Since the volumes of the two figures are in a ratio of 1920:3750, then the surface areas of the figures will be in a ratio of (1920)^(2/3):(3750)^(2/3).
Calculate the ratio:
(1920)^(2/3) = 40(3) = 120
(3750)^(2/3) = 75(5)^2 = 375
Therefore, the surface area of the smaller figure is 120 m squared.