If you have 66.6 g NH,, how many grams of F, are required for complete reaction?
The balanced equation for the reaction between NH3 and F2 is:
2NH3 + 3F2 -> 6HF + N2
From the equation, we can see that 2 moles of NH3 react with 3 moles of F2 to produce 6 moles of HF.
First, we need to convert the given mass of NH3 to moles:
66.6 g NH3 x (1 mol NH3 / 17.031 g NH3) = 3.91 mol NH3
Now we can use the mole ratio from the balanced equation to determine the moles of F2 required:
3.91 mol NH3 x (3 mol F2 / 2 mol NH3) = 5.86 mol F2
Finally, we convert the moles of F2 to grams:
5.86 mol F2 x (38.00 g F2 / 1 mol F2) = 222.68 g F2
Therefore, 222.68 grams of F2 are required for the complete reaction.