Kelly is rolling dice. she rolls 2 dice 30 times, she gets 6 at least one time in the 2 rolls 10 times. what is the probability of her getting 6 at least one time rolling 2 dice?

To calculate the probability of Kelly getting at least one 6 when rolling two dice, we need to determine the probability of not getting a 6 in any of the 2 rolls.

The probability of not getting a 6 in one roll of a single die is 5/6. Since there are two rolls in each experiment, the probability of not getting a 6 in both rolls is (5/6) * (5/6) = 25/36.

Therefore, the probability of getting at least one 6 in two rolls of a pair of dice is 1 - (25/36) = 11/36.

So, the probability of Kelly getting at least one 6 when rolling 2 dice is 11/36 or approximately 0.3056.

ty can you put that in a percent pls

Sure, the probability of Kelly getting at least one 6 when rolling 2 dice is approximately 30.56%.

Suppose you rolled the two number cubes 100 times, how do you think your data might change?

If Kelly were to roll the two dice 100 times, the overall probability of getting at least one 6 when rolling two dice would remain approximately the same at around 30.56%. This is because the probability of getting at least one 6 in two rolls of a pair of dice is constant and does not change based on the number of times the dice are rolled. However, with a larger sample size (100 rolls), the experimental results would likely approach the theoretical probability of 30.56% more closely.