A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards.
Express your answer in percent form rounding to the nearest hundredth. (1 point)
The probability of drawing a diamond on the first draw is 13/52 (since there are 13 diamonds out of 52 cards).
After drawing a diamond on the first draw, there would be 12 diamonds left and 51 total cards left. Hence, the probability of drawing a diamond on the second draw, given that a diamond was drawn on the first draw, is 12/51.
Multiplying these probabilities together gives us:
(13/52) * (12/51) = 156/2652 ≈ 0.0588
Converting to percent form and rounding to the nearest hundredth gives us 5.88%.
Therefore, the probability of drawing two diamond cards is 5.88%.