write the equation of the linear function that passes through the points (-8, 1) and (-6, 3)
To find the equation of the linear function that passes through the points (-8, 1) and (-6, 3), we first need to calculate the slope of the line using the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) = (-8, 1) and (x2, y2) = (-6, 3)
m = (3 - 1) / (-6 - (-8))
m = 2 / 2
m = 1
Now that we have the slope, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
Substitute in one of the points, for example (-8, 1):
y - 1 = 1(x - (-8))
y - 1 = x + 8
y = x + 9
Therefore, the equation of the linear function that passes through the points (-8, 1) and (-6, 3) is y = x + 9.