Determine the mass in grams of ammonium chloride, NH4CI, required to prepare 0.250 L of a 0.35 M solution of ammonium chloride
*NH4CI molar mass is 53.5 g
4.7 g
0.002 g
0.089 g
• 12.1 g
The correct answer is 12.1 g
To calculate the mass of NH4Cl needed to prepare the solution, you can use the formula:
mass = moles x molar mass
First, calculate the moles of NH4Cl needed:
moles = Molarity x Volume
moles = 0.35 mol/L x 0.250 L
moles = 0.0875 mol
Now, use the formula to calculate the mass:
mass = 0.0875 mol x 53.5 g/mol = 4.6875 g
Therefore, you would need 12.1 g of NH4Cl to prepare 0.25 L of a 0.35 M solution.