A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
Responses
21/190
Start Fraction 21 over 190 End Fraction
7/80
Start Fraction 7 over 80 End Fraction
3/5
Start Fraction 3 over 5 End Fraction
7/76
To calculate the probability of selecting an apple and a banana, we first need to find the total number of ways to choose 2 fruits out of the total fruits in the basket.
Total number of fruits = 5 bananas + 8 mangoes + 7 apples = 20 fruits
Therefore, total number of ways to choose 2 fruits out of 20 = 20C2 = (20*19) / (2*1) = 190
Next, we need to find the number of ways to choose 1 apple and 1 banana.
Number of ways to choose 1 apple out of 7 apples = 7C1 = 7
Number of ways to choose 1 banana out of 5 bananas = 5C1 = 5
Total number of ways to choose 1 apple and 1 banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = Number of ways to choose 1 apple and 1 banana / Total number of ways to choose 2 fruits
= 35 / 190
= 7 / 38
So, the correct answer is 7/38.