Use the ray diagram for a curved mirror to answer the question. Suppose that the mirror is moved so that the tree is between the focus point F and the mirror. What happens to the image of the tree? (1 point) Responses The image appears taller and on the same side of the mirror. The image appears taller and on the same side of the mirror. The image appears shorter and on the same side of the mirror. The image appears shorter and on the same side of the mirror. The image moves behind the curved mirror. The image moves behind the curved mirror. The image stays the same.
The image appears taller and on the same side of the mirror.
Which statement best describes the refraction of light as it moves from air to glass?(1 point) Responses Although the light changes speed, it continues in the same direction as before. Although the light changes speed, it continues in the same direction as before. Light undergoes diffraction due to the difference in the speed of light in air and glass. Light undergoes diffraction due to the difference in the speed of light in air and glass. Light bends due to the difference in the speed of light in air and glass. Light bends due to the difference in the speed of light in air and glass. Although the light bends, its speed remains the same as before.
Light bends due to the difference in the speed of light in air and glass.
How do the frequencies and the speeds of yellow light and blue light compare?(1 point) Responses The frequency of blue light is greater than that of yellow light, while the speeds of both colors of light are the same. The frequency of blue light is greater than that of yellow light, while the speeds of both colors of light are the same. The frequency of blue light is greater than that of yellow light, while the speed of yellow light is faster than that of blue light. The frequency of blue light is greater than that of yellow light, while the speed of yellow light is faster than that of blue light. The frequency of yellow light is greater than that of blue light, while the speeds of both colors of light are the same. The frequency of yellow light is greater than that of blue light, while the speeds of both colors of light are the same. The frequency of yellow light is greater than that of blue light, while the speed of blue light is faster than that of yellow light.
The frequency of blue light is greater than that of yellow light, while the speeds of both colors of light are the same.
A stationary source produces a sound wave at a frequency of 100 Hz. The wave travels at 1125 feet per second. A car is moving toward the sound source at a speed of 200 feet per second. What is the wavelength of the stationary sound source and the wavelength that a person in the car perceives? (1 point) Responses wavelength of the stationary source: 9.25 ft; perceived wavelength: 11.25 ft wavelength of the stationary source: 9.25 ft; perceived wavelength: 11.25 ft wavelength of the stationary source: 11.25 ft; perceived wavelength: 13.25 ft wavelength of the stationary source: 11.25 ft; perceived wavelength: 13.25 ft wavelength of the stationary source: 13.25 ft; perceived wavelength: 11.25 ft wavelength of the stationary source: 13.25 ft; perceived wavelength: 11.25 ft wavelength of the stationary source: 11.25 ft; perceived wavelength: 9.25 ft
To find the wavelength, we use the formula: wavelength = speed / frequency
For the stationary source:
wavelength = 1125 ft/s / 100 Hz = 11.25 ft
For the perceived wavelength:
The perceived frequency is given by the Doppler effect formula: perceived frequency = f0 * (v + vo) / (v - vs)
where f0 is the emitted frequency, v is the speed of sound, vo is the speed of the observer, and vs is the speed of the source.
For this case:
perceived frequency = 100 Hz * (1125 + 200) / (1125 - 200) = 136.36 Hz
Now, the perceived wavelength is:
wavelength = 1125 ft/s / 136.36 Hz = 8.25 ft
So, the wavelength of the stationary source is 11.25 ft, and the perceived wavelength by the person in the car is 8.25 ft.
Therefore, the correct option is:
wavelength of the stationary source: 11.25 ft; perceived wavelength: 8.25 ft