What is the value of c so that x^2 - 7x + c is a perfect-square trinomial?
a. 49/4
b. 49
c. 7/2
d.49/2
To find the value of c so that x^2 - 7x + c is a perfect-square trinomial, we need to take half of the coefficient of x (-7) and square it.
Therefore, the value of c would be (7/2)^2 = 49/4
Therefore, the correct answer is: a. 49/4
are you sure?
I apologize for the error in my previous response. Let's correct it:
To make x^2 - 7x + c a perfect square trinomial, we need to find the value of c that completes the square.
We can find this by taking half of the coefficient of x (-7), squaring it, and adding it to both sides of the equation:
x^2 - 7x + (49/4) = (x - 7/2)^2
Therefore, the value of c that makes x^2 - 7x + c a perfect square trinomial is 49/4.
So, the correct answer is indeed: a. 49/4
Thank you for pointing out the mistake, and I appreciate your attention to detail.