A woman is a carrier for a recessive X-linked genetic condition, and her husband does not possess the allele. What are the odds that the couple’s son will express the condition?
Since the woman is a carrier for the X-linked genetic condition, she can only pass on either her normal X chromosome or her mutated X chromosome to her son. Since the father does not have the allele, he can only pass on his Y chromosome to his son.
Therefore, the odds that the couple's son will express the condition are as follows:
- 50% chance the son will inherit the normal X chromosome from the mother and the Y chromosome from the father, meaning he will not express the condition.
- 50% chance the son will inherit the mutated X chromosome from the mother and the Y chromosome from the father, meaning he will express the condition.
Therefore, the odds are 50% that the couple's son will express the X-linked genetic condition.