The frequency of two alleles in a gene pool is 0.17 (A) and 0.83(a). Assume that the population
is in Hardy-Weinberg equilibrium.
Calculate the percentage of heterozygous individuals in the population.
a
46%
b
31%
c
1%
d
28%
The percentage of heterozygous individuals in the population can be calculated using the Hardy-Weinberg equation:
2pq = 2(0.17)(0.83) = 0.2822
Therefore, the percentage of heterozygous individuals in the population is 28% which corresponds to option d.