A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage
of the circuit?
(1 point)
V = IR
0.625 A
14.4 A
0.4 A
2.5 A
To calculate the amperage of the circuit, you can use Ohm's Law:
V = IR
First, calculate the total voltage of the circuit:
Vtotal = Vbattery1 + Vbattery2 + Vbattery3 + Vbattery4
Vtotal = 1.5 V + 1.5 V + 1.5 V + 1.5 V
Vtotal = 6 V
Now, calculate the total resistance of the circuit:
Rtotal = Rbulb
Rtotal = 2.4 ohms
Now, you can calculate the amperage of the circuit using Ohm's Law:
I = V/R
I = Vtotal / Rtotal
I = 6 V / 2.4 ohms
I = 2.5 A
Therefore, the amperage of the circuit is 2.5 A.
So, the correct answer is 2.5 A.