Find the domain of f(x)=-sqrt x^2-16
The domain of a function is all the possible input values (x-values) for which the function is defined.
In this case, the function is f(x) = -√(x^2 - 16).
We know that taking the square root of a negative number is not defined in the real number system. Therefore, the expression inside the square root, x^2 - 16, must be greater than or equal to 0 for the function to be defined.
So, x^2 - 16 ≥ 0
x^2 ≥ 16
x ≥ 4 or x ≤ -4
Therefore, the domain of the function f(x) = -√(x^2 - 16) is all real numbers such that x is greater than or equal to 4 or x is less than or equal to -4.