Using elimination methods solve: 5a-2b=14
2a+2b=14
First, let's write the equations in a system:
5a - 2b = 14
2a + 2b = 14
Now we can eliminate one of the variables by adding the two equations together:
(5a - 2b) + (2a + 2b) = 14
5a - 2b + 2a + 2b = 14
7a = 14
Now we can solve for 'a' by dividing both sides by 7:
a = 2
Now that we have the value of 'a', we can substitute it back into one of the original equations to solve for 'b'. Let's use the first equation:
5(2) - 2b = 14
10 - 2b = 14
-2b = 4
b = -2
Therefore, the solution to the system of equations is a = 2 and b = -2.