The Bayard high school boosters are selling hotdogs and pretzels at the concession stand. They have 300 hotdogs and pretzels in stock and want to earn an income of $800 to sell the hotdogs for four dollars each and the pretzels for two dollars each how many hotdogs and how many pretzels do the boosters need to Cell to reach their goal of $800?

Question

The Bayard high school boosters are selling hotdogs and pretzels at the concession stand. They have 300 hotdogs and pretzels in stock and want to earn an income of $800 to sell the hotdogs for four dollars each and the pretzels for two dollars each how many hotdogs and how many pretzels do the boosters need to Cell to reach their goal of $800?

Answer 1

Let the number of hotdogs sold be represented by H and the number of pretzels sold be represented by P.

The total income from selling hotdogs and pretzels can be represented by the equation: 4H + 2P = 800

Since there are a total of 300 hotdogs and pretzels in stock, we can also write the equation: H + P = 300

Now we can solve these two equations simultaneously:

1) H + P = 300
2) 4H + 2P = 800

Multiplying equation 1 by 2, we get: 2H + 2P = 600

Subtracting equation 2 from this new equation, we get: 2H = 200
H = 100

Substitute the value of H back into equation 1 to solve for P: 100 + P = 300
P = 200

Therefore, the boosters need to sell 100 hotdogs and 200 pretzels to reach their goal of $800.