Surface Area of Triangular Prisms Practice

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Question
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An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined one on top of the other. All 4 sides of the middle rectangle are drawn with dashed lines. The length of the rectangles is 8 meters. The width of all the rectangles is 4 meters. Two identical triangles adjoin the middle rectangle at the left and right with the perpendicular height of the triangles measuring 3.4 meters.

What is the surface area of the triangular prism whose net is shown below? Round the answer to the nearest hundredth.

(1 point)
a
m2

Surface area = 2(base area) + (perimeter of base)(height)

Base area = 8m * 4m = 32m^2

Perimeter of base = 8m + 8m + 4m + 4m = 24m

Height = 3.4m

Surface area = 2(32m^2) + (24m)(3.4m)
Surface area = 64m^2 + 81.6m^2
Surface area = 145.6m^2

Rounded to the nearest hundredth, the surface area is 145.60 m².