A water tank is in the shape of a right circular cylinder. The diameter is 8 feet, and the height is 21.5 feet. Find the surface area of the water tank.
Use 3.14 for n.
To find the surface area of the water tank, we need to calculate the area of the two circular bases and the lateral surface area of the cylinder.
1. Area of the circular bases:
The radius of the cylinder is half of the diameter, so the radius is 8 ft / 2 = 4 ft.
The area of one circular base is A = πr^2, so A = 3.14 * (4 ft)^2 = 3.14 * 16 = 50.24 sq ft.
Since there are two circular bases, the total area of the circular bases is 2 * 50.24 = 100.48 sq ft.
2. Lateral surface area of the cylinder:
The lateral surface area of a cylinder is given by the formula A = 2πrh, where r is the radius and h is the height.
So, the lateral surface area is A = 2 * 3.14 * 4 ft * 21.5 ft = 540.16 sq ft.
Therefore, the total surface area of the water tank is 100.48 sq ft (circular bases) + 540.16 sq ft (lateral surface) = 640.64 sq ft.