Question
What is the zero of the function?
f(x)=x^2+x−42/x^2+3x−28
Enter your answer in the box.
To find the zero of the function f(x), we need to set f(x) equal to 0 and solve for x:
f(x) = 0
x^2 + x - 42 / x^2 + 3x - 28 = 0
To simplify the equation, let's factor the numerator and denominator:
(x+7)(x-6) / (x+7)(x-4) = 0
Now, we can cancel out the common factor (x+7):
(x-6) / (x-4) = 0
Setting the numerator equal to zero:
x-6 = 0
x = 6
Therefore, the zero of the function f(x) is x = 6.