A 60 kg man is standing on the 35 kg high table which is at rest on a horizontal floor. Determine the magnitude of the normal force that
(i) the floor exerts on the table and (il) the table exerts on the man.
(i) 343 N; (ii) 588 N
(i) 931 N; (ii) 588 N (i 1100 N; (i) 600 N
(i) 120 N; (ii) 521 N
No option is correct
The correct answers are:
(i) The magnitude of the normal force that the floor exerts on the table is equal to the weight of the table and the man combined, since they are both at rest. This can be calculated as:
Weight of table = mass * gravity = 35 kg * 9.8 m/s^2 = 343 N
Weight of man = 60 kg * 9.8 m/s^2 = 588 N
Therefore, the total weight on the table is 343 N + 588 N = 931 N
So, the normal force exerted by the floor on the table is 931 N.
(ii) The magnitude of the normal force that the table exerts on the man is equal to the weight of the man, since they are both at rest and in contact with each other. This is equal to:
Weight of man = 60 kg * 9.8 m/s^2 = 588 N
Therefore, the normal force exerted by the table on the man is 588 N.
Therefore, the correct answer is:
(i) 931 N; (ii) 588 N