Solve the system of two equations using elimination with multiplication.
4x - 6y = -48
-2x + 4y = 30
a. (-3,6)
b. (-33,-9)
c. (-21,-6)
d. (3,9)
To solve this system of equations using elimination with multiplication, we will first need to multiply the second equation by 2 so that we can eliminate the x variable when we add the two equations together.
4x - 6y = -48
-2x + 4y = 30
2(-2x + 4y) = 2(30)
-4x + 8y = 60
Now we will add the two equations together:
4x - 6y + (-4x + 8y) = -48 + 60
2y = 12
y = 6
Now that we have the value of y, we can substitute it back into one of the original equations to find the value of x:
4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3
Therefore, the solution to the system of equations is (-3, 6), so the answer is:
a. (-3, 6)